5x^2+11x=2=0

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Solution for 5x^2+11x=2=0 equation:



5x^2+11x=2=0
We move all terms to the left:
5x^2+11x-(2)=0
a = 5; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·5·(-2)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{161}}{2*5}=\frac{-11-\sqrt{161}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{161}}{2*5}=\frac{-11+\sqrt{161}}{10} $

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